 | | From: | Nathan | | Subject: | Yr11 2 Unit/3Unit Algebra Help Problem Solving | | Date: | 6 Jan 2005 02:15:16 -0800 |
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 | Hi there could somone help me with either of these problems please dont think I am trying to get anyone to do my homework, I had around 250+ Prep questions to do and have done them all except for the few I have posted on this newsgroup. I have also attempted to show my working out.
Thanks For your Help Nathan
Question 1 ---------- In a right angle triange the hypotonuse is 15cm If the 2nd side is twice the length of the 3rd calculate the length of the shortest side My Working: (a^2)+(b^2)=(c^2)
=(2x^2)+(x^2)=15^2 =(2x^2)+(x^2)=225
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 | | From: | James Midolo | | Subject: | Re: Yr11 2 Unit/3Unit Algebra Help Problem Solving | | Date: | Fri, 7 Jan 2005 07:40:00 +0800 |
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 | "Nathan" wrote in message news:1105006516.814527.12580@c13g2000cwb.googlegroups.com...
> Question 1 > ---------- > In a right angle triange the hypotonuse is 15cm > If the 2nd side is twice the length of the 3rd calculate the length of > the shortest side > My Working: > (a^2)+(b^2)=(c^2) > > =(2x^2)+(x^2)=15^2 > =(2x^2)+(x^2)=225
a^2 + b^2 = 15^2 b = 2a
a^2 + (2a)^2 = 225 a^2 + 4a^2 = 225 5a^2 = 225 5a^2 - 225 = 0 a = 6.708 b = 13.416
The shortest side is approximately 6.708cm. The answer has an exact value (which could be simplified) of: (sqr(4500)/10)cm.
Regards, James Midolo
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 | | From: | Nathan | | Subject: | Re: Yr11 2 Unit/3Unit Algebra Help Problem Solving | | Date: | 6 Jan 2005 17:21:14 -0800 |
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 | Hi there thank you fo rmaking this clear to me Sincerly Nathan
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